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In isosceles △ABC with AB = AC, BD ⟂ AC and CE ⟂ AB. Which pair of triangles shows BD = CE, and by which rule?

Class 9SAS, ASA and AAS CongruenceGeometry — Triangles
  • A△ABD ≅ △ACE by RHS only
  • B△ABD ≅ △ACE by SAS
  • C△ABD ≅ △ACE by AAS
  • D△BDC ≅ △CEB by SSS

Step-by-Step Solution

∠ADB = ∠AEC = 90°, ∠A is common, AB = AC (opposite the right angles). AAS gives △ABD ≅ △ACE, so BD = CE.
Answer: C) △ABD ≅ △ACE by AAS

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