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AD is an altitude of an isosceles triangle ABC in which AB = AC.
Show which rule proves triangle ABD congruent to triangle ACD and what it implies about BD and DC.

Class 9SSS and RHS CongruenceGeometry — Triangles
  • ARHS; BD = DC, so AD bisects BC
  • BSSS; BD not equal to DC
  • CAAA; AD halves angle B only
  • DSSA; BD = 2 DC

Step-by-Step Solution

Right angles at D, AB = AC (hypotenuses), AD common: RHS gives triangle ABD ≅ triangle ACD, hence BD = DC by CPCT, so AD bisects BC.
Answer: A) RHS; BD = DC, so AD bisects BC

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