- ARHS; BD = DC, so AD bisects BC
- BSSS; BD not equal to DC
- CAAA; AD halves angle B only
- DSSA; BD = 2 DC
Step-by-Step Solution
Right angles at D, AB = AC (hypotenuses), AD common: RHS gives triangle ABD ≅ triangle ACD, hence BD = DC by CPCT, so AD bisects BC.
Answer: A) RHS; BD = DC, so AD bisects BC