In triangle ABC, the perpendiculars from B and C to the opposite sides are equal: BE = CF, where BE is perpendicular to AC and CF perpendicular to AB. Using right triangles BEC and CFB (with common hypotenuse BC), which rule proves them congruent?

Question

Accepted Answer

RHS. Right angles at E and F, common hypotenuse BC, and BE = CF (given equal legs): the right triangles are congruent by RHS.

In triangle ABC, the perpendiculars from B and C to the opposite sides are equal: BE = CF, where BE is perpendicular to AC and CF perpendicular to AB.
Using right triangles BEC and CFB (with common hypotenuse BC), which rule proves them congruent?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 SSS and RHS Congruence practice

In triangle ABC, the perpendiculars from B and C to the opposite sides are equal: BE = CF, where BE is perpendicular to AC and CF perpendicular to AB.Using right triangles BEC and CFB (with common hypotenuse BC), which rule proves them congruent?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 SSS and RHS Congruence practice

In triangle ABC, the perpendiculars from B and C to the opposite sides are equal: BE = CF, where BE is perpendicular to AC and CF perpendicular to AB.
Using right triangles BEC and CFB (with common hypotenuse BC), which rule proves them congruent?