A planetarium dome in Kolkata is a hemisphere of inner radius 21 m. It is to be carpeted on the curved inner surface and the flat circular floor. Find the total area to be carpeted (take π = 22/7). (CSA = curved surface area, TSA = total surface area)

Question

Accepted Answer

4158 m^2. Total = TSA of hemisphere = 3*π*r^2 = 3 * (22/7) * 21 * 21 = 3 * 22 * 3 * 21 = 4158 m^2.

A planetarium dome in Kolkata is a hemisphere of inner radius 21 m.
It is to be carpeted on the curved inner surface and the flat circular floor.
Find the total area to be carpeted (take π = 22/7). (CSA = curved surface area, TSA = total surface area)

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More Class 9 Surface Area of a Sphere practice

A planetarium dome in Kolkata is a hemisphere of inner radius 21 m.It is to be carpeted on the curved inner surface and the flat circular floor.Find the total area to be carpeted (take π = 22/7). (CSA = curved surface area, TSA = total surface area)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Surface Area of a Sphere practice

A planetarium dome in Kolkata is a hemisphere of inner radius 21 m.
It is to be carpeted on the curved inner surface and the flat circular floor.
Find the total area to be carpeted (take π = 22/7). (CSA = curved surface area, TSA = total surface area)