A polynomial p(x) = x^3 - 6x^2 + 11x - 6 is known to have x = 1, x = 2 and x = 3 among its zeroes. A student claims the SUM of all the zeroes equals the value you get by adding these three. What is the sum of all the zeroes of p(x)?

Question

Accepted Answer

6. Check: p(x) = (x - 1)(x - 2)(x - 3), so the three zeroes are 1, 2, 3 and there are no others (degree 3). Their sum is 1 + 2 + 3 = 6.

A polynomial $p (x) = x^{3} - 6 x^{2} + 11 x - 6$ is known to have $x = 1, x = 2$ and $x = 3$ among its zeroes.
A student claims the SUM of all the zeroes equals the value you get by adding these three.
What is the sum of all the zeroes of $p (x)$ ?

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More Class 9 Zeroes of a Polynomial practice

A polynomial p(x)=x3−6x2+11x−6 is known to have x=1,x=2 and x=3 among its zeroes.A student claims the SUM of all the zeroes equals the value you get by adding these three.What is the sum of all the zeroes of p(x)?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Zeroes of a Polynomial practice

A polynomial $p (x) = x^{3} - 6 x^{2} + 11 x - 6$ is known to have $x = 1, x = 2$ and $x = 3$ among its zeroes.
A student claims the SUM of all the zeroes equals the value you get by adding these three.
What is the sum of all the zeroes of $p (x)$ ?