A flower pot is a frustum 14 cm deep whose top rim has radius 6 cm and whose base has radius 3 cm. Find its capacity in cm³. Take π = 22/7.

Question

Accepted Answer

924. Volume = (1/3)πh(R² + Rr + r²) = (1/3) × (22/7) × 14 × (36 + 18 + 9) = (1/3) × 44 × 63 = 924 cm³. (Dropping the 1/3 gives 2772; leaving out the middle term Rr gives 660; treating the pot as a plain cylinder of the wider radius gives 1584.)

A flower pot is a frustum 14 cm deep whose top rim has radius 6 cm and whose base has radius 3 cm. Find its capacity in $cm^{3}$ . Take π = 22/7.

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A flower pot is a frustum 14 cm deep whose top rim has radius 6 cm and whose base has radius 3 cm. Find its capacity in cm3. Take π = 22/7.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Areas & Volumes practice

A flower pot is a frustum 14 cm deep whose top rim has radius 6 cm and whose base has radius 3 cm. Find its capacity in $cm^{3}$ . Take π = 22/7.