Find the roots of both equations and state how $x$ compares with $y$. I. $x^2+13x+42=0$
II. $y^2+2y=24$

I: $(x+6)(x+7)$ → $x=-6$, −7. II: rewrite as $y^2+2y-24=0$ → $(y+6)(y-4)$ → $y=-6$, 4. Both $x$-roots sit at or below −6, the smaller $y$-root, and −6 = −6 makes equality possible: $x$ ≤ $y$.