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Solve for $x$ and $y$ , then select the correct relation. I. $x^{2} - 2 x - 15 = 0$
II. $y^{2} + 12 y + 35 = 0$

Competition practiceQuadratic Comparison

A $x$ ≤ $y$
B $x < y$
C $x$ ≥ $y$
D $x > y$

Step-by-Step Solution

I:

(x - 5) (x + 3)

→

x = 5

, −3. II:

(y + 5) (y + 7)

→

y = - 5

, −7. Even the smaller

x

(−3) lies above the larger

y

(−5), so

x > y

for every pairing.

Answer: D)

x > y

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