In the following two equations, solve for $x$ and $y$ and choose the correct relation. I. $x^{2} - 13 x + 42 = 0$
II. $y^{2} - 7 y + 12 = 0$

Question

In the following two equations, solve for x and y and choose the correct relation. I. x^2 - 13x + 42 = 0 II. y^2 - 7y + 12 = 0

Accepted Answer

x > y. I: (x−6)(x−7)=0 → x = 6, 7. II: (y−3)(y−4)=0 → y = 3, 4. Every x-root is strictly greater than every y-root, so x > y.

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