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I. $x^{2} - 3 x - 10 = 0$
II. $y^{2} + 5 y + 6 = 0$ . Establish the relation between $x$ and $y$ .

Competition practiceQuadratic Comparison

A $x >= y$
B $x < y$
Crelation cannot be established
D $x > y$

Step-by-Step Solution

x = 5

or -2 and

y = - 2

or -3; every

x

is at least every

y

(5 > both; -2 >= -2 and -2 > -3), so

x >= y

.

Answer: A)

x >= y

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