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I. $x^{2} - 8 x + 12 = 0$
II. $y^{2} - 7 y + 10 = 0$ . Establish the relation between $x$ and $y$ .

Competition practiceQuadratic Comparison

A $x < y$
B $x$ ≥ $y$
Crelation cannot be established
D $x > y$

Step-by-Step Solution

x = 2

or 6;

y = 2

or 5.

x = 2, y = 5

gives

x < y

but

x = 6, y = 2

gives

x > y

, so no single relation holds.

Answer: C) relation cannot be established

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