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Solve both equations and compare $x$ and $y$ . I: $x^{2} - 4 x + 3 = 0$ . II: $y^{2} - 16 y + 63 = 0$ .

Competition practiceQuadratic Comparison

A $x$ ≤ $y$
B $x > y$
C $x$ ≥ $y$
D $x < y$

Step-by-Step Solution

x = 1

or 3 and

y = 7

or 9; the largest

x

(3) is less than the smallest

y

(7), so

x < y

.

Answer: D)

x < y

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