A cyclist has 60 km to cover. If he could raise his speed by 5 km/h he would get there one hour sooner. His usual speed (in km/h) is:

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Accepted Answer

15. 60/v − 60/(v + 5) = 1 gives 300 = v² + 5v, so v² + 5v − 300 = 0 and v = 15 km/h (4 hours instead of 3). 20 km/h is the RAISED speed, and 60/5 = 12 divides the distance by the increase in speed, which has no meaning here.

A cyclist has 60 km to cover. If he could raise his speed by 5 km/h he would get there one hour sooner. His usual speed (in km/h) is:

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