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A flagstaff 6 m tall stands upright on the top of a tower. From a point on the ground the angles of elevation of the top of the flagstaff and the top of the tower are 60° and 45°. The height of the tower is:

Competition practiceTrigonometry
  • A3(√3 + 1) m
  • B3(√3 − 1) m
  • C6(√3 + 1) m
  • D2√3 m

Step-by-Step Solution

Let the tower be h and the ground distance d. From the 45° angle, d = h. From the 60° angle, (h + 6)/h = tan60° = √3, so h(√3 − 1) = 6 and h = 6/(√3 − 1) = 3(√3 + 1) ≈ 8.20 m.
Answer: A) 3(√3 + 1) m

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