From the top of a 7 m building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°. Find the total height of the cable tower (in m). (Take √(3) = 1.73.)

Question

Accepted Answer

19.11. Depression of foot 45: horizontal distance d = 7 (tan45 = 7/d). Elevation of top 60: extra above building = d tan60 = 7 √3 = 7 x 1.73 = 12.11. Total = 7 + 12.11 = 19.11 m.

From the top of a 7 m building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°.
Find the total height of the cable tower (in m). (Take √(3) = 1.73.)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

From the top of a 7 m building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°.Find the total height of the cable tower (in m). (Take √(3) = 1.73.)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

From the top of a 7 m building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°.
Find the total height of the cable tower (in m). (Take √(3) = 1.73.)