Practice30Create account

Find the value of tan 5° · tan 25° · tan 45° · tan 65° · tan 85°.

Class 10Introduction to TrigonometryTrigonometry
  • A0
  • B
  • C1
  • D5

Step-by-Step Solution

Pair the angles that add to 90°: tan 85° = tan(90° − 5°) = cot 5°, so tan 5° · tan 85° = 1. Likewise tan 25° · tan 65° = 1. With tan 45° = 1, the whole product is 1 · 1 · 1 = 1.
Answer: C) 1

Key idea: Why ratios — and not lengths

Two right triangles with the same acute angle θ are SIMILAR (Class 10 ch. 6 — AA criterion: both have a right angle and the angle θ).

Similar triangles → corresponding sides in fixed ratio.
So the ratio (opposite / hypotenuse) takes the SAME value in any right triangle with angle θ — regardless of how big the triangle is.

That's why sin θ, cos θ, tan θ are FUNCTIONS of the angle alone — they're well-defined.

This is the fundamental reason trigonometry works as a clean theory.

Master this chapter in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Introduction to Trigonometry practice questions

More Class 10 Introduction to Trigonometry practice

For an acute angle θ, simplify √1 - ^2 θ/ ^2 θ.Simplify: (cosec θ − cot θ)(cosec θ + cot θ).For any angle θ, the expression (sin θ + cos θ)² + (sin θ − cos θ)² always equals:A student claims that for some angle θ, sin θ = 4/3. Is this possible?Two right triangles of very different sizes each contain the same acute angle θ. How do…