A step-deviation table has equal class size h = 5, f_i = 60 and f_i u_i = -24 . The mean of the data is 32. What assumed mean a was used?

Question

Accepted Answer

34. Mean = a + h ( f_i u_i/ f_i ) , so 32 = a + 5 (-24/60 ) = a - 2 , giving a = 34. "30" reverses the sign of the correction; "32" assumes a must equal the mean; "56" adds the whole 24 instead of the correction h × -24/60 = -2 .

A step-deviation table has equal class size $h = 5, \sum f_{i} = 60$ and $\sum f_{i} u_{i} = - 24$ . The mean of the data is 32. What assumed mean a was used?

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More Class 10 Mean of Grouped Data practice

A step-deviation table has equal class size h=5,∑fi​=60 and ∑fi​ui​=−24. The mean of the data is 32. What assumed mean a was used?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Mean of Grouped Data practice

A step-deviation table has equal class size $h = 5, \sum f_{i} = 60$ and $\sum f_{i} u_{i} = - 24$ . The mean of the data is 32. What assumed mean a was used?