For the equation (k+1)x^2 - 6(k+1)x + 9 = 0 to have equal roots (k not -1), find the value of k. Work through the discriminant condition step by step.

Question

Accepted Answer

0. D = 0: [6(k+1)]^2 - 4(k+1)(9) = 0 => 36(k+1)^2 - 36(k+1) = 0 => 36(k+1)[(k+1)-1] = 0 => (k+1)(k) = 0. Since k != -1, k = 0.

For the equation $(k + 1) x^{2} - 6 (k + 1) x + 9 = 0$ to have equal roots $(k$ not -1), find the value of $k$ .
Work through the discriminant condition step by step.

Step-by-Step Solution

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More Class 10 Nature of Roots (Discriminant) practice

For the equation (k+1)x2−6(k+1)x+9=0 to have equal roots (k not -1), find the value of k.Work through the discriminant condition step by step.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Nature of Roots (Discriminant) practice

For the equation $(k + 1) x^{2} - 6 (k + 1) x + 9 = 0$ to have equal roots $(k$ not -1), find the value of $k$ .
Work through the discriminant condition step by step.