The sum of squares of two consecutive odd positive integers is 130.
If the smaller integer is $x$ , the equation becomes $2 x^{2} + 4 x - 126 = 0$ .
What is the smaller integer?

Question

The sum of squares of two consecutive odd positive integers is 130. If the smaller integer is x, the equation becomes 2x^2 + 4x - 126 = 0. What is the smaller integer?

Accepted Answer

7. 2x^2 + 4x - 126 = 0 divides to x^2 + 2x - 63 = 0 = (x - 7)(x + 9). Positive root x = 7 (integers 7 and 9: 49 + 81 = 130).

The sum of squares of two consecutive odd positive integers is 130.
If the smaller integer is $x$ , the equation becomes $2 x^{2} + 4 x - 126 = 0$ .
What is the smaller integer?

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More Class 10 Standard Form and Roots practice

The sum of squares of two consecutive odd positive integers is 130.If the smaller integer is x, the equation becomes 2x2+4x−126=0.What is the smaller integer?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Standard Form and Roots practice

The sum of squares of two consecutive odd positive integers is 130.
If the smaller integer is $x$ , the equation becomes $2 x^{2} + 4 x - 126 = 0$ .
What is the smaller integer?