Two towns P and Q are 240 km apart. A car starts from P and another from Q at the same moment. If they drive in the same direction they meet after 6 hours; if they drive towards each other they meet after 2 hours. Find the speed of the faster car.

Let the speeds be $x$ and $y$ km/h with $x$ the faster. Driving the same way, the faster car closes the 240 km gap at $(x-y)$ km/h in 6 hours, so $x-y=40$. Driving towards each other they close it at $(x+y)$ km/h in 2 hours, so $x+y=120$. Adding: $2x=160,x=80$ and $y=40$. Check: 80 - 40 = 40 and 80 + 40 = 120. 40 km/h is the slower car's speed, which here is also the difference of the speeds, so it traps twice; 120 km/h is their combined speed; 60 km/h assumes the two cars are equally fast.