A shopkeeper in Jaipur models his daily profit (in hundreds of Rs) by p(x) = x^2 - 9x + 20, where x is the hour of the day. The profit is zero at two hours. Using factorisation, find the LARGER of these two hours.

Question

Accepted Answer

5. x^2 - 9x + 20 = (x - 4)(x - 5), so zeros are x = 4 and x = 5. The larger value is 5.

A shopkeeper in Jaipur models his daily profit (in hundreds of Rs) by $p (x) = x^{2} - 9 x + 20$ , where $x$ is the hour of the day.
The profit is zero at two hours. Using factorisation, find the LARGER of these two hours.

Step-by-Step Solution

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More Class 9 Factor Theorem and Factorisation practice

A shopkeeper in Jaipur models his daily profit (in hundreds of Rs) by p(x)=x2−9x+20, where x is the hour of the day.The profit is zero at two hours. Using factorisation, find the LARGER of these two hours.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Factor Theorem and Factorisation practice

A shopkeeper in Jaipur models his daily profit (in hundreds of Rs) by $p (x) = x^{2} - 9 x + 20$ , where $x$ is the hour of the day.
The profit is zero at two hours. Using factorisation, find the LARGER of these two hours.