Arjun writes a cubic p(x) = x^3 - 7x + 6. He notices that p(1) = 0, so (x - 1) is one factor. After dividing, he gets the quotient x^2 + x - 6. Factorise the full cubic completely.

Question

Accepted Answer

(x - 1)(x - 2)(x + 3). x^2 + x - 6 = (x - 2)(x + 3). So p(x) = (x - 1)(x - 2)(x + 3). Check p(2)=8-14+6=0 and p(-3)=-27+21+6=0.

Arjun writes a cubic $p (x) = x^{3} - 7 x + 6$ .
He notices that $p (1) = 0$ , so $(x - 1)$ is one factor.
After dividing, he gets the quotient $x^{2} + x - 6$ .
Factorise the full cubic completely.

Step-by-Step Solution

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More Class 9 Factor Theorem and Factorisation practice

Arjun writes a cubic p(x)=x3−7x+6.He notices that p(1)=0, so (x−1) is one factor.After dividing, he gets the quotient x2+x−6.Factorise the full cubic completely.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Factor Theorem and Factorisation practice

Arjun writes a cubic $p (x) = x^{3} - 7 x + 6$ .
He notices that $p (1) = 0$ , so $(x - 1)$ is one factor.
After dividing, he gets the quotient $x^{2} + x - 6$ .
Factorise the full cubic completely.