Suppose (x - 2) and (x + 2) are both factors of p(x) = x^3 + ax^2 - 4x + b. Using p(2) = 0 and p(-2) = 0, find the value of a + b.

Question

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0. p(2) = 8 + 4a - 8 + b = 4a + b = 0. p(-2) = -8 + 4a + 8 + b = 4a + b = 0. Both give 4a + b = 0. With a = 0, b = 0 satisfying both (and p(x)=x^3-4x=x(x-2)(x+2)), a + b = 0.

Suppose $(x - 2)$ and $(x + 2)$ are both factors of $p (x) = x^{3} + a x^{2} - 4 x + b$ .
Using $p (2) = 0$ and $p (- 2) = 0$ , find the value of $a + b$ .

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More Class 9 Factor Theorem and Factorisation practice

Suppose (x−2) and (x+2) are both factors of p(x)=x3+ax2−4x+b.Using p(2)=0 and p(−2)=0, find the value of a+b.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Factor Theorem and Factorisation practice

Suppose $(x - 2)$ and $(x + 2)$ are both factors of $p (x) = x^{3} + a x^{2} - 4 x + b$ .
Using $p (2) = 0$ and $p (- 2) = 0$ , find the value of $a + b$ .