Meena claims that if you add the three roots of x^3 - 6x^2 + 11x - 6, you get the same number you would obtain another way. This cubic factorises as (x - 1)(x - 2)(x - 3). What is the sum of its three roots?

Question

Accepted Answer

6. Roots are 1, 2 and 3. Their sum is 1 + 2 + 3 = 6 (which equals the coefficient of x^2 with sign changed).

Meena claims that if you add the three roots of $x^{3} - 6 x^{2} + 11 x - 6$ , you get the same number you would obtain another way.
This cubic factorises as $(x - 1) (x - 2) (x - 3)$ .
What is the sum of its three roots?

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More Class 9 Factor Theorem and Factorisation practice

Meena claims that if you add the three roots of x3−6x2+11x−6, you get the same number you would obtain another way.This cubic factorises as (x−1)(x−2)(x−3).What is the sum of its three roots?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Factor Theorem and Factorisation practice

Meena claims that if you add the three roots of $x^{3} - 6 x^{2} + 11 x - 6$ , you get the same number you would obtain another way.
This cubic factorises as $(x - 1) (x - 2) (x - 3)$ .
What is the sum of its three roots?