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Find the remainder when $p (x) = 4 x^{3} - 12 x^{2} + 14 x - 3$ is divided by $(2 x - 1)$ .

Class 9Remainder TheoremPolynomials

A $\frac{3}{2}$
B1
C0
D $- \frac{3}{2}$

Step-by-Step Solution

2 x - 1 = 0

gives

x = \frac{1}{2}

. p

(\frac{1}{2}) = 4 (\frac{1}{8}) - 12 (\frac{1}{4}) + 14 (\frac{1}{2}) - 3 = 0.5 - 3 + 7 - 3 = 1.5 = \frac{3}{2}

.

Answer: A)

\frac{3}{2}

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