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A polynomial $p (x) = x^{2} + (m - 3) x - 12$ has $x = 4$ as one of its zeroes.
Find the value of $m$ .

Class 9Zeroes of a PolynomialPolynomials

A1
B3
C4
D2

Step-by-Step Solution

p(4) = 0: 16 + 4(m - 3) - 12 = 0, so 16 + 4m - 12 - 12 = 0, giving 4m - 8 = 0, m = 2.

Answer: D) 2

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