An aeroplane at height 3000 m observes two ships sailing toward it in the same vertical plane. The angles of depression are 30° and 45°. Find the distance (in m) between the two ships.

Question

Accepted Answer

3000(√3 - 1). Near ship (45°): d1 = 3000. Far ship (30°): d2 = 3000 √3. Distance = 3000 √3 - 3000 = 3000(√3 - 1) m.

An aeroplane at height 3000 m observes two ships sailing toward it in the same vertical plane.
The angles of depression are 30° and 45°.
Find the distance (in m) between the two ships.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

An aeroplane at height 3000 m observes two ships sailing toward it in the same vertical plane.The angles of depression are 30° and 45°.Find the distance (in m) between the two ships.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

An aeroplane at height 3000 m observes two ships sailing toward it in the same vertical plane.
The angles of depression are 30° and 45°.
Find the distance (in m) between the two ships.