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If sin = cos°), where is an acute angle, find A.

Class 10Introduction to TrigonometryTrigonometry
  • A26°
  • B29°
  • C16°
  • D32°

Step-by-Step Solution

Turn the cosine into a sine: cos°) = sin(90° − °)) = sin(116° − A). Equating the acute angles, ° − A, so ° and °. (Check: sin 87° = cos 3°.)
Answer: B) 29°

Key idea: Why ratios — and not lengths

Two right triangles with the same acute angle θ are SIMILAR (Class 10 ch. 6 — AA criterion: both have a right angle and the angle θ).

Similar triangles → corresponding sides in fixed ratio.
So the ratio (opposite / hypotenuse) takes the SAME value in any right triangle with angle θ — regardless of how big the triangle is.

That's why sin θ, cos θ, tan θ are FUNCTIONS of the angle alone — they're well-defined.

This is the fundamental reason trigonometry works as a clean theory.

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