A shopkeeper in Jaipur models his daily profit (in Rs hundreds) by P = -x^2 + 6x - 9, where x is the number of items (in dozens). For what nature do the roots of -x^2 + 6x - 9 = 0 fall, i.e. when is the profit zero?

Question

Accepted Answer

Real and equal (one value of x). Multiply by -1: x^2 - 6x + 9 = 0. D = 36 - 36 = 0, so roots are real and equal; profit is zero at exactly one value of x.

A shopkeeper in Jaipur models his daily profit (in Rs hundreds) by $P = - x^{2} + 6 x - 9$ , where $x$ is the number of items (in dozens).
For what nature do the roots of $- x^{2} + 6 x - 9 = 0$ fall, i.e. when is the profit zero?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Nature of Roots (Discriminant) practice

A shopkeeper in Jaipur models his daily profit (in Rs hundreds) by P=−x2+6x−9, where x is the number of items (in dozens).For what nature do the roots of −x2+6x−9=0 fall, i.e. when is the profit zero?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Nature of Roots (Discriminant) practice

A shopkeeper in Jaipur models his daily profit (in Rs hundreds) by $P = - x^{2} + 6 x - 9$ , where $x$ is the number of items (in dozens).
For what nature do the roots of $- x^{2} + 6 x - 9 = 0$ fall, i.e. when is the profit zero?