Consider three two-digit numbers whose square is exactly 100 more than 21 times the number itself.
If the number is $x$ , write the equation in standard form and find the value of $x$ .

Question

Consider three two-digit numbers whose square is exactly 100 more than 21 times the number itself. If the number is x, write the equation in standard form and find the value of x.

Accepted Answer

25. x^2 = 21x + 100 gives x^2 - 21x - 100 = 0 = (x - 25)(x + 4). The positive two-digit solution is x = 25.

Consider three two-digit numbers whose square is exactly 100 more than 21 times the number itself.
If the number is $x$ , write the equation in standard form and find the value of $x$ .

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Standard Form and Roots practice

Consider three two-digit numbers whose square is exactly 100 more than 21 times the number itself.If the number is x, write the equation in standard form and find the value of x.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Standard Form and Roots practice

Consider three two-digit numbers whose square is exactly 100 more than 21 times the number itself.
If the number is $x$ , write the equation in standard form and find the value of $x$ .