A number x and its square give x^2 = 6x - 9 in a geometry problem. Rewriting as p(x) = x^2 - 6x + 9 = 0, how many DISTINCT zeroes does this polynomial have?

Question

Accepted Answer

1. x^2 - 6x + 9 = (x - 3)^2, so the only zero is x = 3 (a repeated zero). It has 1 distinct zero.

A number $x$ and its square give $x^{2} = 6 x - 9$ in a geometry problem.
Rewriting as $p (x) = x^{2} - 6 x + 9 = 0$ , how many DISTINCT zeroes does this polynomial have?

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More Class 9 Zeroes of a Polynomial practice

A number x and its square give x2=6x−9 in a geometry problem.Rewriting as p(x)=x2−6x+9=0, how many DISTINCT zeroes does this polynomial have?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Zeroes of a Polynomial practice

A number $x$ and its square give $x^{2} = 6 x - 9$ in a geometry problem.
Rewriting as $p (x) = x^{2} - 6 x + 9 = 0$ , how many DISTINCT zeroes does this polynomial have?