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If $x = \frac{1}{2}$ is a zero of $p (x) = 2 x^{2} + k x - 1$ , find the value of $k$ .

Class 9Zeroes of a PolynomialPolynomials

A3
B2
C0
D1

Step-by-Step Solution

p

(\frac{1}{2}) = 0 : 2 (\frac{1}{4}) + k (\frac{1}{2}) - 1 = 0

, so

\frac{1}{2} + \frac{k}{2} - 1 = 0

, giving

\frac{k}{2} = \frac{1}{2}, k = 1

.

Answer: D) 1

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